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Dynamic digital holographic interferometry with three wavelengths

Nazif Demoli, Dalibor Vukicevic, and Marc Torzynski

Open Access Open Access

Abstract

A color digital holographic interferometry movie was produced by applying the subtraction digital holography method in a quasi-Fourier off-axis experimental setup. The movie was numerically recorded and replayed from three sets of digital holograms obtained with three different laser lines (476 nm, 532 nm, and 647 nm). The movie shows convective flows induced by thermal dissipation in a tank filled with oil.

©2003 Optical Society of America

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Figures (6)
Fig. 1.
Fig. 1. Experimental setup for recording quasi-Fourier off-axis digital holograms.

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Fig. 2.
Fig. 2. Phase object used in experiments.

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Fig. 3.
Fig. 3. Object reconstruction obtained from the three monochromatic digital holograms.

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Fig. 4.
Fig. 4. First four color digital holographic interferograms.

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Fig. 5.
Fig. 5. Red component of the color interferograms shown in Fig. 4.

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Fig. 6.
Fig. 6. (1.76 MB) Color movie of convective flows induced by thermal dissipation, composed from the sequence of digital holographic interferometry images.

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Equations (14)

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u x 1 y 1 = R 0 δ x 1 − x 0 y 1 − y 0 + S 0 exp [ i 2 π λ ∫ n x 1 y 1 z d z ] ,
u x 2 y 2 = R 0 C 0 exp { i ψ x 2 y 2 } + s x 2 y 2 ,
〈 ∣ s x 2 y 2 ∣ 〉 = α · S 0 ,
I ( x 2 , y 2 ) = ( R 0 λd ) 2 + ∣ s ( x 2 , y 2 ) ∣ 2
+ R 0 λd s ( x 2 , y 2 ) exp [ − i ψ ( x 2 , y 2 ) ] + R 0 λd s * ( x 2 , y 2 ) exp [ i ψ ( x 2 , y 2 ) ] ,
I ( x 2 , y 2 , t n ) = ( R 0 λd ) 2 + ∣ s ( x 2 , y 2 , t n ) ∣ 2
+ R 0 λd s ( x 2 , y 2 , t n ) exp [ − i ψ ( x 2 , y 2 ) ] + R 0 λd s * ( x 2 , y 2 , t n ) exp [ i ψ ( x 2 , y 2 ) ]
Δ I ( x 2 , y 2 , t n ) = I ( x 2 , y 2 , t 0 ) − I ( x 2 , y 2 , t n )
∝ [ s ( x 2 , y 2 , t 0 ) − s ( x 2 , y 2 , t n ) ] exp [ − i ψ ( x 2 , y 2 ) ] + C C
∝ ∣ s ( x 2 , y 2 , t n ) ∣ exp [ i φ ( x 2 , y 2 , t 0 ) + φ ( x 2 , y 2 , t n ) 2 ] × sin ⁡ [ Δ φ ( x 2 , y 2 , t n ) 2 ]
× exp [ − i π λd ( x 2 2 + y 2 2 ) ] × exp [ − i 2 π λd ( x 2 x 0 + y 2 y 0 ) ] + C C ,
Δ φ ( x 2 , y 2 , t n ) = 2 π λ ∫ Δ n ( x 2 , y 2 , z , t n ) d z ,
Δ n ( x 2 , y 2 , z , t n ) = n ( x 2 , y 2 , z , t 0 ) − n ( x 2 , y 2 , z , t n )
∫ Δ n ( x 2 , y 2 , z , t n ) d z = m λ ( x 2 , y 2 , t n ) λ , m λ = 0 , 1 , 2 , …
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