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Polarization Bloch waves in photonic crystals based on vertical cavity surface emitting laser arrays

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Abstract

The vectorial model of two-dimensional photonic crystals based on coherently coupled arrays of Vertical Cavity Surface - Emitting Lasers (VCSELs) is proposed in non-Hermitian Hamiltonian eigenproblem formulation. The polarization modes of square-symmetry photonic lattices are investigated theoretically. Rich mode structure with complimentary patterns of intensity for orthogonal polarizations of electromagnetic Bloch wave is predicted. The predicted near-field patterns of the polarization modes are confirmed in measurements of InGaAs/AlGaAs VCSEL arrays emitting at 965nm wavelength.

©2004 Optical Society of America

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Figures (5)

Fig.1. .
Fig.1. . odel of the VCSEL-based photonic crystal (a), Brillouin zone of the equivalent 3D photonic crystal (b), empty lattice test (dashed lines) and simplified diagram of the energy bands Ω m K = ( n Re ω m K c ) 2 K z 2 π Λ (solid lines) (c).
Fig. 2.
Fig. 2. Calculated intensity patterns of the main polarization components at the Δ, Z, and T points of the Brillouin zone ; arrows show the polarization direction.
Fig. 3.
Fig. 3. Losses of different modes as a function of the pattern fill factor FF (ratio of the areas of the high-reflectivity pixel and of the unit cell).
Fig. 4.
Fig. 4. Structure of the electromagnetic field of the main lasing mode of a VCSEL array (|T 5,〉 photonic mode, ξ = π Λ K z ).
Fig. 5.
Fig. 5. Measured polarization-resolved NF intensity pattern of the |T 5,〉 state of a continuous - wave lasing 4×4 VCSEL array.

Equations (6)

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D = ε E + [ H × g ] , B = μ H + [ g × E ] , g = z ̂ i c ω ln r ( x , y ) N δ ( z 2 N L )
[ m o ( c n ) 2 + p ̂ 2 2 m o + i c n ln ( r ( x , y ) ) 2 L ] | v m K = ω m K | v m K , m 0 = K z n c
E ̂ | T 5 , x ̂ x ̂ cos ( π Λ x ) cos ( π Λ y ) z ̂ i π Λ K z sin ( π Λ x ) cos ( π Λ y ) + y ̂ π 2 2 Λ 2 K z 2 sin ( π Λ x ) sin ( π Λ y )
E ̂ T 5 , y ̂ y ̂ cos ( π Λ x ) cos ( π Λ y ) z ̂ i π Λ K z cos ( π Λ x ) sin ( π Λ y ) + x ̂ π 2 2 Λ 2 K z 2 sin ( π Λ x ) sin ( π Λ y )
E ( 2 ) = y ̂ π 2 2 Λ 2 K z 2 f ( x , y ) sin ( π Λ x ) sin ( π Λ y ) + y ̂ π 2 Λ K z 2 { f y sin ( π Λ x ) cos ( π Λ y ) + f x ( π Λ x ) sin ( π Λ y ) }
+ y ̂ 1 2 K z 2 cos ( π Λ x ) cos ( π Λ y ) 2 f ( x , y ) x y
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