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Comparative analysis of Bragg fibers

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Abstract

In this paper, we compare three analysis methods for Bragg fibers, viz. the transfer matrix method, the asymptotic method and the Galerkin method. We also show that with minor modifications, the transfer matrix method is able to calculate exactly the leakage loss of Bragg fibers due to a finite number of H/L layers. This approach is more straightforward than the commonly used Chew’s method. It is shown that the asymptotic approximation condition should be satisfied in order to get accurate results. The TE and TM modes, and the band gap structures are analyzed using Galerkin method.

©2004 Optical Society of America

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Figures (6)

Fig. 1.
Fig. 1. Bragg modes and band gap structures calculated by transfer matrix method. Left: TE, Right: TM.
Fig. 2.
Fig. 2. TE01 and TM01 at k=1.2 in the Bragg fiber, calculated by transfer matrix method. Left: TE, Right: TM.
Fig. 3.
Fig. 3. Mode field of TE01, TM01 at k=1.2 by asymptotic method. Left: TE, Right: TM.
Fig. 4.
Fig. 4. The index profile of a Bragg fiber in Galerkin method.
Fig. 5.
Fig. 5. Band gap and Bragg modes obtained by Galerkin method. Left: TE, Right: TM.
Fig. 6.
Fig. 6. Mode fields of Bragg mode by Galerkin method. Left: TE, Right: TM.

Tables (1)

Tables Icon

Table 1. Comparison of calculated effective indices by three methods at k 0 =1.2

Equations (16)

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[ E z H ϕ H z E ϕ ] = [ J m ( k i r ) Y m ( k i r ) 0 0 i ω ε k i J m ( k i r ) i ω ε k i Y m ( k i r ) m β k i 2 r J m ( k i r ) m β k i 2 r Y m ( k i r ) 0 0 J m ( k i r ) Y m ( k i r ) m β k i 2 r J m ( k i r ) m β k i 2 r Y m ( k i r ) i ω μ k i J m ( k i r ) i ω μ k i Y m ( k i r ) ] [ A B C D ]
[ A 1 B 1 C 1 D 1 ] = [ T 11 T 12 T 13 T 14 T 21 T 22 T 23 T 24 T 31 T 32 T 33 T 34 T 41 T 42 T 43 T 44 ] [ A N B N C N D N ]
[ E z H ϕ H z E ϕ ] = [ H m I ( k i r ) H m II ( k i r ) 0 0 i ω ε k i H m I ( k i r ) i ω ε k i H m II ( k i r ) m β k i 2 r H m I ( k i r ) m β k i 2 r H m II ( k i r ) 0 0 H m I ( k i r ) H m II ( k i r ) m β k i 2 r H m I ( k i r ) m β k i 2 r H m I ( k i r ) i ω μ k i H m i ( k i r ) i ω μ k i H m II ( k i r ) ] [ A N B N C N D N ]
[ A 1 B 1 C 1 D 1 ] = [ T 11 T 12 T 13 T 14 T 21 T 22 T 23 T 24 T 31 T 32 T 33 T 34 T 41 T 42 T 43 T 44 ] [ A N B N C N D N ]
[ T ] = [ T ] × [ 1 1 0 0 i i 0 0 0 0 1 1 0 0 i i ]
[ T 21 T 23 T 41 T 43 ] [ A N C N ] = 0
det [ T 21 T 23 T 41 T 43 ] = 0 .
Loss = 40 π λ ln 10 Im ( n eff )
d 2 f dr 2 + 1 r df dr + ( k 0 2 n 2 β 2 1 r 2 ) f = 0
d 2 g dr 2 + 1 r dg dr + ( k 0 2 n 2 β 2 1 r 2 ) g d ln n 2 dr ( dg dr + 1 r g ) = 0
x = σ r 2 / a 2 , h ( r ) = n 2 ( r ) n cl 2 n co 2 n cl 2 ,
V 2 = k 0 2 a 2 ( n co 2 n cl 2 ) , b = ( β / k 0 ) 2 n cl 2 n co 2 n cl 2
f ( x ) = i = 0 N 1 a i φ i ( x ) , g ( x ) = i = 0 N 1 b i φ i ( x )
φ i ( x ) = i ! ( i + m ) ! e x / 2 x m / 2 L i ( m ) ( x )
L i ( m ) ( x ) = k = 0 i ( i + m ) ! ( i k ) ! ( k + m ) ! k ! ( x ) k
[ M ] [ A ] = b [ A ]
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